A lactometer is used to: MCQ with Answer and Explanation

A lactometer is used to:
A. Measure liquid density
B. Measure milk purity
C. Measure wind speed
D. Measure humidity
Answer: Option B
Solution (By JKExamLibrary)
Lactometer is a specialized hydrometer for measuring milk purity/density. It works on Archimedes' principle: pure milk has specific density; adulteration (with water) changes density, altering lactometer reading. While it measures density, its specific application is milk testing. Option B is partially correct but not specific; competitive exams expect the precise application. Memory tip: 'Lacto = milk; meter = measure'. This application-based question tests knowledge of scientific instruments in daily life, frequently appearing in competitive exams. Always note context-specific uses of general instruments.

This question belongs to: Science Physics

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1 Report Error
An echo is heard from a cliff after 3 s. If speed of sound is 340 m/s, distance of cliff is
A. 170 m
B. 340 m
C. 1020 m
D. 510 m

Correct Answer: Option D


Explanation:
d = v × t / 2 = 340 × 3 / 2 = 510 m.

This question belongs to: Science Physics
Question #2 Report Error
The time period of a simple pendulum depends on
A. Nature of bob material
B. Amplitude of swing
C. Mass of bob
D. Length of pendulum and g

Correct Answer: Option D


Explanation:
T = 2π√(L/g). For small amplitudes, period independent of amplitude and mass. Depends only on effective length and acceleration due to gravity. Used in pendulum clocks.

This question belongs to: Science Physics
Question #3 Report Error
A body weighs 72 N on the surface of the Earth. What is the gravitational force on it at a height equal to half the radius of the Earth?
A. 72 N
B. 28 N
C. 16 N
D. 32 N

Correct Answer: Option D


Explanation:
Weight on surface W = mg = 72 N. Acceleration due to gravity at height h is g' = g [R / (R+h)]². Here h = R/2. So, g' = g [R / (R + R/2)]² = g [1 / (3/2)]² = g (2/3)² = 4g/9. The new weight W' = mg' = m(4g/9) = (4/9)mg = (4/9) × 72 = 32 N.

This question belongs to: Science Physics