A legal clerk walks from his residence to the courthouse at 5 km/h and arrives 15 minutes late. If he sets a pace of 7.5 km/h, he arrives 5 minutes early. Find the distance. MCQ with Answer and Explanation
A legal clerk walks from his residence to the courthouse at 5 km/h and arrives 15 minutes late. If he sets a pace of 7.5 km/h, he arrives 5 minutes early. Find the distance.
A. 6.0 km
B. 5.0 km
C. 5.5 km
D. 4.5 km
Answer: Option B
Solution (By JKExamLibrary)
Time difference = 15 - (-5) = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d/5 - d/7.5 = 1/3 => (1.5d - d) / 7.5 = 1/3 => 0.5d / 7.5 = 1/3 => d / 15 = 1/3 => d = 5 km.
The speed indices of two sprinters are in the ratio 3 : 4. If the first sprinter requires 24 seconds to wrap up a bend, how much time does the second sprinter require?
Explanation:
Ratio of speeds = 3:4, so ratio of times required = 4:3. Given 4 parts = 24 seconds => 1 part = 6 seconds. Time for the second sprinter = 3 parts = 3 * 6 = 18 seconds.
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