A luxury car handles a tracking route sector of 240 km. It finishes the first half segment stretch at 40 km/h and the second half sector at 60 km/h. Find the mean average speed recorded across the full route. MCQ with Answer and Explanation
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Question #1
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Walking at 5/7 of his usual speed, a man reaches his destination 24 minutes late. What is his usual time?
Correct Answer: Option C
Explanation:
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A truck covers 60 km at 30 km/h and then another 100 km at 50 km/h. Find the overall average speed for the full transit.
Correct Answer: Option A
Explanation:
Total distance = 60 + 100 = 160 km. Time for first leg = 60 / 30 = 2 hours. Time for second leg = 100 / 50 = 2 hours. Total time = 4 hours. Average speed = 160 / 4 = 40 km/h.
Total distance = 60 + 100 = 160 km. Time for first leg = 60 / 30 = 2 hours. Time for second leg = 100 / 50 = 2 hours. Total time = 4 hours. Average speed = 160 / 4 = 40 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A car covers a certain distance at an average speed of 60 km/h in 4 hours. At what speed must it travel to cover the same distance in 3 hours?
Correct Answer: Option B
Explanation:
Distance = 60 * 4 = 240 km. New required speed = 240 / 3 = 80 km/h.
Distance = 60 * 4 = 240 km. New required speed = 240 / 3 = 80 km/h.
This question belongs to:
Maths
Time Speed and Distance
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