A man can row 6 km/h in still water. If it takes him twice as long to row upstream as to row downstream of a river, then the speed of the stream is: MCQ with Answer and Explanation
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Question #1
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Two points P and Q are 240 km apart. Train A starts from P towards Q at 60 km/h at 9:00 AM. Train B starts from Q towards P at 80 km/h at 10:00 AM. At what time will they meet?
Correct Answer: Option A
Explanation:
By 10:00 AM, Train A covers 60 km. Remaining distance = 240 - 60 = 180 km. Relative speed = 60 + 80 = 140 km/h. Time to meet after 10 AM = 180 / 140 = 9/7 hours = 1 hour and 17 minutes. Meeting time is 11:17 AM.
By 10:00 AM, Train A covers 60 km. Remaining distance = 240 - 60 = 180 km. Relative speed = 60 + 80 = 140 km/h. Time to meet after 10 AM = 180 / 140 = 9/7 hours = 1 hour and 17 minutes. Meeting time is 11:17 AM.
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Maths
Time Speed and Distance
Question #2
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A jogger runs along a square perimeter of side 45 meters. If his speed is 10.8 km/h, how much time does he take to finish one full round?
Correct Answer: Option A
Explanation:
Perimeter of the course = 4 * 45 = 180 meters. Speed = 10.8 km/h = 10.8 * (5/18) = 3 m/s. Time required = Distance / Speed = 180 / 3 = 60 seconds.
Perimeter of the course = 4 * 45 = 180 meters. Speed = 10.8 km/h = 10.8 * (5/18) = 3 m/s. Time required = Distance / Speed = 180 / 3 = 60 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A car covers a certain distance at a speed of 48 km/h in 50 minutes. With what speed should it run to decrease the time of journey by 10 minutes?
Correct Answer: Option B
Explanation:
Original time = 50 mins. New time = 50 - 10 = 40 mins. S1 * T1 = S2 * T2 => 48 * 50 = S2 * 40 => S2 = (48 * 50) / 40 = 60 km/h.
Original time = 50 mins. New time = 50 - 10 = 40 mins. S1 * T1 = S2 * T2 => 48 * 50 = S2 * 40 => S2 = (48 * 50) / 40 = 60 km/h.
This question belongs to:
Maths
Time Speed and Distance
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