A man covers a distance of 24 km in 3 hours. If he doubles his speed, how much time will he take to cover a distance of 32 km? MCQ with Answer and Explanation
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Question #1
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A commuter departs from outpost A at 5:00 AM at 25 km/h. Another starts from A at 7:00 AM at 35 km/h tracking along the same direction corridor. At what distance away from A will they intercept?
Correct Answer: Option C
Explanation:
By 7:00 AM, the first commuter tracks for 2 hours, covering 25 * 2 = 50 km. Relative speed index = 35 - 25 = 10 km/h. Time to intercept = 50 / 10 = 5 hours. Distance path from point A = Speed of second commuter * Intercept Time = 35 * 5 = 175 km.
By 7:00 AM, the first commuter tracks for 2 hours, covering 25 * 2 = 50 km. Relative speed index = 35 - 25 = 10 km/h. Time to intercept = 50 / 10 = 5 hours. Distance path from point A = Speed of second commuter * Intercept Time = 35 * 5 = 175 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Two points M and N are separated by 300 km. At 8:00 AM, a car leaves M for N at 60 km/h. At 9:00 AM, another car leaves N for M at 90 km/h. At what time will they pass each other?
Correct Answer: Option D
Explanation:
By 9:00 AM, the first car covers 60 km * 1 hour = 60 km. The remaining distance between them is 300 - 60 = 240 km. Relative speed = 60 + 90 = 150 km/h. Time to meet after 9:00 AM = 240 / 150 = 8/5 hours = 1 hour 36 minutes. Meeting time = 9:00 AM + 1 hour 36 minutes = 10:36 AM.
By 9:00 AM, the first car covers 60 km * 1 hour = 60 km. The remaining distance between them is 300 - 60 = 240 km. Relative speed = 60 + 90 = 150 km/h. Time to meet after 9:00 AM = 240 / 150 = 8/5 hours = 1 hour 36 minutes. Meeting time = 9:00 AM + 1 hour 36 minutes = 10:36 AM.
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Maths
Time Speed and Distance
Question #3
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Walking at 3/4 of his normal pace, a student is 12 minutes late. Find his usual time.
Correct Answer: Option D
Explanation:
New speed = 3/4 of usual speed => New time = 4/3 of usual time. Difference = 1/3 of usual time = 12 minutes. Usual time = 12 * 3 = 36 minutes.
New speed = 3/4 of usual speed => New time = 4/3 of usual time. Difference = 1/3 of usual time = 12 minutes. Usual time = 12 * 3 = 36 minutes.
This question belongs to:
Maths
Time Speed and Distance
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