Two points M and N are separated by 300 km. At 8:00 AM, a car leaves M for N at 60 km/h. At 9:00 AM, another car leaves N for M at 90 km/h. At what time will they pass each other? MCQ with Answer and Explanation
Two points M and N are separated by 300 km. At 8:00 AM, a car leaves M for N at 60 km/h. At 9:00 AM, another car leaves N for M at 90 km/h. At what time will they pass each other?
A. 10:24 AM
B. 10:36 AM
C. 10:40 AM
D. 10:48 AM
Answer: Option B
Solution (By JKExamLibrary)
By 9:00 AM, the first car covers 60 km * 1 hour = 60 km. The remaining distance between them is 300 - 60 = 240 km. Relative speed = 60 + 90 = 150 km/h. Time to meet after 9:00 AM = 240 / 150 = 8/5 hours = 1 hour 36 minutes. Meeting time = 9:00 AM + 1 hour 36 minutes = 10:36 AM.
A theft is reported at 4:00 AM. The thief runs at 50 km/h. The police begin chasing at 4:30 AM at 60 km/h. Find the distance from the starting point where the thief is caught.
Explanation:
In 30 minutes (0.5 hours), the thief covers 50 * 0.5 = 25 km. Relative speed = 60 - 50 = 10 km/h. Time taken to catch = 25 / 10 = 2.5 hours. Distance covered by police = 60 km/h * 2.5 hours = 150 km.
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