A theft is reported at 4:00 AM. The thief runs at 50 km/h. The police begin chasing at 4:30 AM at 60 km/h. Find the distance from the starting point where the thief is caught. MCQ with Answer and Explanation
A theft is reported at 4:00 AM. The thief runs at 50 km/h. The police begin chasing at 4:30 AM at 60 km/h. Find the distance from the starting point where the thief is caught.
A. 150 km
B. 180 km
C. 120 km
D. 200 km
Answer: Option A
Solution (By JKExamLibrary)
In 30 minutes (0.5 hours), the thief covers 50 * 0.5 = 25 km. Relative speed = 60 - 50 = 10 km/h. Time taken to catch = 25 / 10 = 2.5 hours. Distance covered by police = 60 km/h * 2.5 hours = 150 km.
Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 8 minutes. Usual time = 8 * 4 = 32 minutes.
Explanation:
Speed of first car = 320 / 4 = 80 km/h. Ratio of speeds is 4:5, so 4 parts = 80 km/h => 1 part = 20 km/h. Speed of second car = 5 parts = 5 * 20 = 100 km/h.
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