A theft is reported at 4:00 AM. The thief runs at 50 km/h. The police begin chasing at 4:30 AM at 60 km/h. Find the distance from the starting point where the thief is caught. MCQ with Answer and Explanation

A theft is reported at 4:00 AM. The thief runs at 50 km/h. The police begin chasing at 4:30 AM at 60 km/h. Find the distance from the starting point where the thief is caught.
A. 150 km
B. 180 km
C. 120 km
D. 200 km
Answer: Option A
Solution (By JKExamLibrary)
In 30 minutes (0.5 hours), the thief covers 50 * 0.5 = 25 km. Relative speed = 60 - 50 = 10 km/h. Time taken to catch = 25 / 10 = 2.5 hours. Distance covered by police = 60 km/h * 2.5 hours = 150 km.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A wheel has a radius of 14 cm. How many revolutions must it make to cover a distance of 88 meters?
A. 120
B. 80
C. 150
D. 100

Correct Answer: Option D


Explanation:
Circumference of the wheel = 2 * (22/7) * 14 = 88 cm = 0.88 meters. Total distance = 88 meters. Number of revolutions = 88 / 0.88 = 100.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
Walking at 4/5 of his normal pace, a student is 8 minutes late. Find his usual time.
A. 40 minutes
B. 36 minutes
C. 32 minutes
D. 28 minutes

Correct Answer: Option C


Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 8 minutes. Usual time = 8 * 4 = 32 minutes.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
The ratio between the speeds of two cars is 4 : 5. If the first car covers a distance of 320 km in 4 hours, what is the speed of the second car?
A. 100 km/h
B. 110 km/h
C. 90 km/h
D. 80 km/h

Correct Answer: Option A


Explanation:
Speed of first car = 320 / 4 = 80 km/h. Ratio of speeds is 4:5, so 4 parts = 80 km/h => 1 part = 20 km/h. Speed of second car = 5 parts = 5 * 20 = 100 km/h.

This question belongs to: Maths Time Speed and Distance