Walking at 4/5 of his normal pace, a student is 8 minutes late. Find his usual time. MCQ with Answer and Explanation
Question
Report Error
Discuss this Question (0)
Practice More Time Speed and Distance Questions
Question #1
Report Error
A commuter train passes a standing track post in 6 seconds flat. If the length of the train is 150 meters, find its speed in km/h.
Correct Answer: Option C
Explanation:
Speed = 150 / 6 = 25 m/s. In km/h = 25 * (18/5) = 90 km/h.
Speed = 150 / 6 = 25 m/s. In km/h = 25 * (18/5) = 90 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
Report Error
A walk at 5/6 of usual speed makes a person 10 minutes late. What is his usual time?
Correct Answer: Option A
Explanation:
New Speed = 5/6 of usual speed => New Time = 6/5 of usual time. Difference = 1/5 * Usual Time = 10 minutes => Usual Time = 50 minutes.
New Speed = 5/6 of usual speed => New Time = 6/5 of usual time. Difference = 1/5 * Usual Time = 10 minutes => Usual Time = 50 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #3
Report Error
Two cars start from the same spot and travel along perpendicular roads. One travels at 30 km/h and the other at 40 km/h. Find the distance between them after 1 hour.
Correct Answer: Option A
Explanation:
In 1 hour, the first car travels 30 km and the second car travels 40 km. Direct distance = sqrt(30^2 + 40^2) = sqrt(900 + 1600) = sqrt(2500) = 50 km.
In 1 hour, the first car travels 30 km and the second car travels 40 km. Direct distance = sqrt(30^2 + 40^2) = sqrt(900 + 1600) = sqrt(2500) = 50 km.
This question belongs to:
Maths
Time Speed and Distance
No comments yet. Be the first to start the discussion!