A man covers half of his journey at 40 km/h and the remaining half at 60 km/h. What is his average speed? MCQ with Answer and Explanation
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Question #1
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A boat can row 12 km/h in still water. If the river current flows at 3 km/h, find the time taken to row 45 km downstream.
Correct Answer: Option A
Explanation:
Downstream speed = 12 + 3 = 15 km/h. Time taken = Distance / Downstream speed = 45 / 15 = 3 hours.
Downstream speed = 12 + 3 = 15 km/h. Time taken = Distance / Downstream speed = 45 / 15 = 3 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Two points P and Q are 240 km apart. Train A starts from P towards Q at 60 km/h at 9:00 AM. Train B starts from Q towards P at 80 km/h at 10:00 AM. At what time will they meet?
Correct Answer: Option A
Explanation:
By 10:00 AM, Train A covers 60 km. Remaining distance = 240 - 60 = 180 km. Relative speed = 60 + 80 = 140 km/h. Time to meet after 10 AM = 180 / 140 = 9/7 hours = 1 hour and 17 minutes. Meeting time is 11:17 AM.
By 10:00 AM, Train A covers 60 km. Remaining distance = 240 - 60 = 180 km. Relative speed = 60 + 80 = 140 km/h. Time to meet after 10 AM = 180 / 140 = 9/7 hours = 1 hour and 17 minutes. Meeting time is 11:17 AM.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A driver spans a highway path of 400 km. If the uniform speed is boosted by 10 km/h, the trip wraps up in 2 hours less. Find the initial speed.
Correct Answer: Option D
Explanation:
Let original speed be s. 400/s - 400/(s+10) = 2 => 200/s - 200/(s+10) = 1 => 2000 = s(s+10). Solving s^2 + 10s - 2000 = 0 yields (s-40)(s+50) = 0. Speed = 40 km/h.
Let original speed be s. 400/s - 400/(s+10) = 2 => 200/s - 200/(s+10) = 1 => 2000 = s(s+10). Solving s^2 + 10s - 2000 = 0 yields (s-40)(s+50) = 0. Speed = 40 km/h.
This question belongs to:
Maths
Time Speed and Distance
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