A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet? MCQ with Answer and Explanation
A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
A. 32 km
B. 28 km
C. 20 km
D. 24 km
Answer: Option D
Solution (By JKExamLibrary)
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
Two cars start from the same spot and travel along perpendicular roads. One travels at 15 km/h and the other at 20 km/h. Find the distance between them after 2 hours.
Explanation:
In 2 hours, the first car travels 30 km and the second car travels 40 km. Direct distance = sqrt(30^2 + 40^2) = sqrt(900 + 1600) = sqrt(2500) = 50 km.
A car covers a total distance of 180 km. It travels the first half of the distance at 30 km/h and the second half at 60 km/h. Find the average speed for the full journey.
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