A man rows 10 km/h in still water. If the river current tracks at 2 km/h, it takes him 2.5 hours to row to a point and back. How far is the point? MCQ with Answer and Explanation

A man rows 10 km/h in still water. If the river current tracks at 2 km/h, it takes him 2.5 hours to row to a point and back. How far is the point?
A. 15 km
B. 12 km
C. 14 km
D. 10 km
Answer: Option B
Solution (By JKExamLibrary)
Downstream speed = 10 + 2 = 12 km/h. Upstream speed = 10 - 2 = 8 km/h. Let distance be d. d / 12 + d / 8 = 2.5 => 5d / 24 = 2.5 => 5d = 60 => d = 12 km.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A cyclist covers a 1500-meter course in 5 minutes. Find his speed in km/h.
A. 15 km/h
B. 18 km/h
C. 24 km/h
D. 20 km/h

Correct Answer: Option B


Explanation:
Time = 5 minutes = 300 seconds. Speed = 1500 / 300 = 5 m/s. Converting to km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A person wins a 100-meter race in 12 seconds, while the runner-up finishes in 13 seconds. By what distance did the winner beat the runner-up?
A. 8.12 meters
B. 7.24 meters
C. 7.69 meters
D. 8.50 meters

Correct Answer: Option C


Explanation:
Speed of runner-up = 100 / 13 m/s. Distance covered by runner-up in 12 seconds = (100 / 13) * 12 = 1200 / 13 = 92.31 meters. Beat distance = 100 - 92.31 = 7.69 meters.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A suspect flees at 6:00 AM at a uniform speed of 50 km/h. The enforcement squad tracks pursuit at 7:00 AM at 60 km/h. At what time will the squad apprehend the suspect?
A. 12:00 PM
B. 11:00 AM
C. 2:00 PM
D. 1:00 PM

Correct Answer: Option A


Explanation:
By 7:00 AM, the suspect has traveled for 1 hour and covered 50 km. Relative tracking speed = 60 - 50 = 10 km/h. Time taken to catch = 50 / 10 = 5 hours. Apprehension time = 7:00 AM + 5 hours = 12:00 PM.

This question belongs to: Maths Time Speed and Distance