A man walks at a speed of 6 km/h instead of 5 km/h and thereby covers 12 km more in the same duration. Find the actual distance covered by him at his normal speed. MCQ with Answer and Explanation
A man walks at a speed of 6 km/h instead of 5 km/h and thereby covers 12 km more in the same duration. Find the actual distance covered by him at his normal speed.
A. 60 km
B. 80 km
C. 50 km
D. 72 km
Answer: Option A
Solution (By JKExamLibrary)
Let duration be t hours. Distance difference = 6t - 5t = t = 12 hours. Distance at normal speed (5 km/h) = 5 * 12 = 60 km.
The speeds of two bodies are in the ratio 5 : 6. If they clear the same sector distance, and the slower car takes 3 hours, how much time does the faster car take?
Explanation:
Ratio of speeds = 5:6, so ratio of times taken = 6:5. Slower car takes 6 parts = 3 hours => 1 part = 0.5 hours. Time for faster car = 5 parts = 5 * 0.5 = 2.5 hours.
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