A motorboat maps 32 km downstream in 2 hours and tracks the same upriver stretch upstream in 4 hours. Find the baseline speed of the boat hull in still water. MCQ with Answer and Explanation

A motorboat maps 32 km downstream in 2 hours and tracks the same upriver stretch upstream in 4 hours. Find the baseline speed of the boat hull in still water.
A. 10 km/h
B. 12 km/h
C. 15 km/h
D. 14 km/h
Answer: Option B
Solution (By JKExamLibrary)
Downstream speed = 32 / 2 = 16 km/h. Upstream speed = 32 / 4 = 8 km/h. Speed in still water = (16 + 8) / 2 = 12 km/h.

This question belongs to: Maths Time Speed and Distance

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1 Report Error
A car covers a certain distance at an average speed of 60 km/h in 4 hours. At what speed must it travel to cover the same distance in 3 hours?
A. 80 km/h
B. 90 km/h
C. 85 km/h
D. 75 km/h

Correct Answer: Option A


Explanation:
Distance = 60 * 4 = 240 km. New required speed = 240 / 3 = 80 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A train running at 90 km/h crosses a platform double its length in 36 seconds. What is the length of the platform?
A. 500 meters
B. 400 meters
C. 600 meters
D. 750 meters

Correct Answer: Option C


Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance covered in 36 seconds = 25 * 36 = 900 meters. Let train length be L, so platform length = 2L. L + 2L = 900 => 3L = 900 => L = 300 meters. Platform length = 2L = 600 meters.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A locomotive running at 54 km/h takes 20 seconds to completely cross a platform. If it takes 8 seconds to pass a standing point observer, find the platform length.
A. 220 meters
B. 160 meters
C. 180 meters
D. 200 meters

Correct Answer: Option C


Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Length of train = Speed * Time to cross observer = 15 * 8 = 120 meters. Total distance to cross platform = Speed * Time = 15 * 20 = 300 meters. Platform length = 300 - 120 = 180 meters.

This question belongs to: Maths Time Speed and Distance