A motorcycle travels from terminal A to B at 40 km/h and returns at 60 km/h. What is the average speed for the round journey? MCQ with Answer and Explanation
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Question #1
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A train 140 meters long tracking at 63 km/h passes a modern bridge in 24 seconds. Find the length of the bridge.
Correct Answer: Option D
Explanation:
Speed of train = 63 * (5/18) = 17.5 m/s. Total distance handled in 24 seconds = 17.5 * 24 = 420 meters. Length of the bridge = 420 - 140 = 280 meters.
Speed of train = 63 * (5/18) = 17.5 m/s. Total distance handled in 24 seconds = 17.5 * 24 = 420 meters. Length of the bridge = 420 - 140 = 280 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A passenger train running at 54 km/h passes through a tunnel 400 meters long in 40 seconds. Find the length of the train.
Correct Answer: Option D
Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Total distance covered in 40 seconds = 15 * 40 = 600 meters. Length of train = Total distance - Tunnel length = 600 - 400 = 200 meters.
Speed of train = 54 * (5/18) = 15 m/s. Total distance covered in 40 seconds = 15 * 40 = 600 meters. Length of train = Total distance - Tunnel length = 600 - 400 = 200 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A cyclist tracks a sector distance of 24 km at a certain speed. If he drops his pace by 2 km/h, he takes 1 hour more to cover the route. Find his baseline speed.
Correct Answer: Option B
Explanation:
Let original speed be s. 24 / (s - 2) - 24 / s = 1 => 24(2) = s(s - 2) => 48 = s(s - 2). Solving s^2 - 2s - 48 = 0 yields (s - 8)(s + 6) = 0. Since speed must be positive, s = 8 km/h.
Let original speed be s. 24 / (s - 2) - 24 / s = 1 => 24(2) = s(s - 2) => 48 = s(s - 2). Solving s^2 - 2s - 48 = 0 yields (s - 8)(s + 6) = 0. Since speed must be positive, s = 8 km/h.
This question belongs to:
Maths
Time Speed and Distance
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