A passenger notice that a train passes him in 4 seconds. If the train is 120 meters long, what is its speed in km/h? MCQ with Answer and Explanation
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Question #1
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A thief is noticed by a policeman from a distance of 300 meters. The thief runs at 12 km/h and the policeman chases him at 15 km/h. What is the distance run by the thief before he is caught?
Correct Answer: Option C
Explanation:
Relative speed = 15 - 12 = 3 km/h. Time taken to catch = Initial distance / Relative speed = 0.3 km / 3 km/h = 0.1 hours. Distance covered by thief = Speed of thief * Time = 12 km/h * 0.1 hours = 1.2 km = 1200 meters.
Relative speed = 15 - 12 = 3 km/h. Time taken to catch = Initial distance / Relative speed = 0.3 km / 3 km/h = 0.1 hours. Distance covered by thief = Speed of thief * Time = 12 km/h * 0.1 hours = 1.2 km = 1200 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 120 meters long running at 45 km/h crosses a bridge in 30 seconds. Find the length of the bridge.
Correct Answer: Option D
Explanation:
Speed of train = 45 * (5/18) = 12.5 m/s. Total distance covered in 30 seconds = 12.5 * 30 = 375 meters. Length of bridge = 375 - 120 = 255 meters.
Speed of train = 45 * (5/18) = 12.5 m/s. Total distance covered in 30 seconds = 12.5 * 30 = 375 meters. Length of bridge = 375 - 120 = 255 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A man rides a bicycle at 12 km/h from his house to his school and reaches 5 minutes late. Next day he increases his speed to 15 km/h and reaches 5 minutes early. Find the distance between his house and school.
Correct Answer: Option B
Explanation:
Time difference = 5 - (-5) = 10 minutes = 1/6 hour. Let distance be d. d/12 - d/15 = 1/6 => (5d - 4d)/60 = 1/6 => d/60 = 1/6 => d = 10 km.
Time difference = 5 - (-5) = 10 minutes = 1/6 hour. Let distance be d. d/12 - d/15 = 1/6 => (5d - 4d)/60 = 1/6 => d/60 = 1/6 => d = 10 km.
This question belongs to:
Maths
Time Speed and Distance
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