A person covers 1/3 of a distance at 15 km/h, 1/3 at 30 km/h and the last 1/3 at 60 km/h. Find the average speed. MCQ with Answer and Explanation
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Question #1
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A truck covers 300 meters in 20 seconds. Find its speed in km/h.
Correct Answer: Option A
Explanation:
Speed = 300 / 20 = 15 m/s. In km/h = 15 * (18/5) = 54 km/h.
Speed = 300 / 20 = 15 m/s. In km/h = 15 * (18/5) = 54 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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The speed tracking profile of an express train is exactly 25% higher than a commercial car. Both take off from terminal A together and reach terminal B, 200 km away, at the same instant. On the corridor route, the train logs a total stall of 20 minutes at checkpoints. Find the car speed.
Correct Answer: Option B
Explanation:
Let car speed be c, then train tracking speed is 1.25c. Time difference parameter = 200/c - 200/(1.25c) = 20/60 hours = 1/3 hours. 200/c * (1 - 1/1.25) = 1/3 => 200/c * (0.25/1.25) = 1/3 => 200/c * (1/5) = 1/3 => 40/c = 1/3 => c = 120 km/h.
Let car speed be c, then train tracking speed is 1.25c. Time difference parameter = 200/c - 200/(1.25c) = 20/60 hours = 1/3 hours. 200/c * (1 - 1/1.25) = 1/3 => 200/c * (0.25/1.25) = 1/3 => 200/c * (1/5) = 1/3 => 40/c = 1/3 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A car covers three successive 10 km stretches at speeds of 20 km/h, 30 km/h and 60 km/h respectively. Find its average speed.
Correct Answer: Option B
Explanation:
Total distance = 3 * 10 = 30 km. Total time taken = 10/20 + 10/30 + 10/60 = 1/2 + 1/3 + 1/6 = 1 hour. Average speed = 30 / 1 = 30 km/h.
Total distance = 3 * 10 = 30 km. Total time taken = 10/20 + 10/30 + 10/60 = 1/2 + 1/3 + 1/6 = 1 hour. Average speed = 30 / 1 = 30 km/h.
This question belongs to:
Maths
Time Speed and Distance
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