A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey. MCQ with Answer and Explanation
A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey.
A. 15 km
B. 20 km
C. 18 km
D. 12 km
Answer: Option A
Solution (By JKExamLibrary)
Let the one-way distance be d. Time taken for forward journey = d / 15, and return journey = d / 5. Given: d/15 + d/5 = 4. Multiplying by 15: d + 3d = 60 => 4d = 60 => d = 15 km.
A thief is spotted by a policeman from a distance of 250 meters. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief to be 10 km/h and that of the policeman to be 12 km/h, how far will the thief have run before he is overtaken?
Explanation:
Relative speed = 12 - 10 = 2 km/h. Time taken to catch the thief = 0.25 km / 2 km/h = 1/8 hour. Distance run by the thief = Speed * Time = 10 km/h * (1/8) hour = 1.25 km = 1250 meters.
A thief is spotted by a policeman from a distance of 150 meters. The thief runs at 11 km/h and the policeman chases him at 12 km/h. Find the distance covered by the thief before he is caught.
Explanation:
Relative speed = 12 - 11 = 1 km/h. Time to catch the thief = 0.15 km / 1 km/h = 0.15 hours. Distance covered by thief = Speed * Time = 11 km/h * 0.15 hours = 1.65 km = 1650 meters.
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