A thief is spotted by a policeman from a distance of 250 meters. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief to be 10 km/h and that of the policeman to be 12 km/h, how far will the thief have run before he is overtaken? MCQ with Answer and Explanation
A thief is spotted by a policeman from a distance of 250 meters. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief to be 10 km/h and that of the policeman to be 12 km/h, how far will the thief have run before he is overtaken?
A. 1250 meters
B. 1000 meters
C. 1750 meters
D. 1500 meters
Answer: Option A
Solution (By JKExamLibrary)
Relative speed = 12 - 10 = 2 km/h. Time taken to catch the thief = 0.25 km / 2 km/h = 1/8 hour. Distance run by the thief = Speed * Time = 10 km/h * (1/8) hour = 1.25 km = 1250 meters.
Excluding institutional stops, the speed of an intercity coach is 72 km/h and including stops it is 60 km/h. For how many minutes does the coach stop per hour?
Explanation:
Speed of B = 400 / 50 = 8 m/s. Distance covered by B when A crosses the finish line at 44 seconds = 8 * 44 = 352 meters. Winning margin = 400 - 352 = 48 meters.
Explanation:
New speed = 6/7 of usual speed => New time = 7/6 of usual time. Difference = 1/6 of usual time = 15 minutes. Usual time = 15 * 6 = 90 minutes.
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