Excluding institutional stops, the speed of an intercity coach is 72 km/h and including stops it is 60 km/h. For how many minutes does the coach stop per hour? MCQ with Answer and Explanation
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Question #1
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A runner covers 200 meters in 22 seconds. Find his approximate speed in km/h.
Correct Answer: Option C
Explanation:
Speed = 200 / 22 m/s = 100 / 11 m/s. In km/h = (100 / 11) * (18/5) = 360 / 11 = 32.72 km/h.
Speed = 200 / 22 m/s = 100 / 11 m/s. In km/h = (100 / 11) * (18/5) = 360 / 11 = 32.72 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A traveler covers 1/3 of a distance at 20 km/h and the remaining 2/3 at 50 km/h. What is his net average speed for the entire distance?
Correct Answer: Option B
Explanation:
Let the total distance be 150 km. First part = 50 km; Time = 50/20 = 2.5 hours. Remaining part = 100 km; Time = 100/50 = 2 hours. Total distance = 150 km, Total time = 4.5 hours. Average speed = 150 / 4.5 = 1500 / 45 = 34.28 km/h.
Let the total distance be 150 km. First part = 50 km; Time = 50/20 = 2.5 hours. Remaining part = 100 km; Time = 100/50 = 2 hours. Total distance = 150 km, Total time = 4.5 hours. Average speed = 150 / 4.5 = 1500 / 45 = 34.28 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A person covers a certain distance at a certain speed. If he reduces his speed by 20%, he takes 15 minutes more to cover the same distance. Find his usual time.
Correct Answer: Option C
Explanation:
New Speed = 0.8 * Usual Speed. Since distance is constant, New Time = Usual Time / 0.8 = 1.25 * Usual Time. Increase in time = 0.25 * Usual Time = 15 minutes. Usual Time = 15 / 0.25 = 60 minutes.
New Speed = 0.8 * Usual Speed. Since distance is constant, New Time = Usual Time / 0.8 = 1.25 * Usual Time. Increase in time = 0.25 * Usual Time = 15 minutes. Usual Time = 15 / 0.25 = 60 minutes.
This question belongs to:
Maths
Time Speed and Distance
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