A traveler covers 1/3 of a distance at 20 km/h and the remaining 2/3 at 50 km/h. What is his net average speed for the entire distance? MCQ with Answer and Explanation

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A traveler covers 1/3 of a distance at 20 km/h and the remaining 2/3 at 50 km/h. What is his net average speed for the entire distance?

A. 36.50 km/h

B. 32.5 km/h

C. 38.00 km/h

D. 34.28 km/h

Answer: Option D

Solution (By JKExamLibrary)

Let the total distance be 150 km. First part = 50 km; Time = 50/20 = 2.5 hours. Remaining part = 100 km; Time = 100/50 = 2 hours. Total distance = 150 km, Total time = 4.5 hours. Average speed = 150 / 4.5 = 1500 / 45 = 34.28 km/h.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error

A commuter departs from outpost A at 5:00 AM at 25 km/h. Another starts from A at 7:00 AM at 35 km/h tracking along the same direction corridor. At what distance away from A will they intercept?

A. 175 km

B. 195 km

C. 185 km

D. 165 km

View Answer & Solution Discuss

Correct Answer: Option A

Explanation:
By 7:00 AM, the first commuter tracks for 2 hours, covering 25 * 2 = 50 km. Relative speed index = 35 - 25 = 10 km/h. Time to intercept = 50 / 10 = 5 hours. Distance path from point A = Speed of second commuter * Intercept Time = 35 * 5 = 175 km.

This question belongs to: Maths Time Speed and Distance

Question #2 Report Error

A person wins a 100-meter race in 12 seconds, while the runner-up finishes in 13 seconds. By what distance did the winner beat the runner-up?

A. 7.24 meters

B. 8.12 meters

C. 7.69 meters

D. 8.50 meters

View Answer & Solution Discuss

Correct Answer: Option C

Explanation:
Speed of runner-up = 100 / 13 m/s. Distance covered by runner-up in 12 seconds = (100 / 13) * 12 = 1200 / 13 = 92.31 meters. Beat distance = 100 - 92.31 = 7.69 meters.

This question belongs to: Maths Time Speed and Distance