A person covers a distance of 12 km in 1 hour 30 minutes. What is his speed in meters per second? MCQ with Answer and Explanation
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Question #1
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A vehicle covers a lap distance of 450 km at a uniform speed. If its velocity is cut by 15 km/h, the trip maps 1.5 hours longer. Find the original speed.
Correct Answer: Option A
Explanation:
Let original speed be s. 450/(s-15) - 450/s = 1.5 => 300/(s-15) - 300/s = 1 => 300(15) = s(s-15) => 4500 = s(s-15). Solving s^2 - 15s - 4500 = 0 gives (s-75)(s+60) = 0. Baseline speed = 75 km/h.
Let original speed be s. 450/(s-15) - 450/s = 1.5 => 300/(s-15) - 300/s = 1 => 300(15) = s(s-15) => 4500 = s(s-15). Solving s^2 - 15s - 4500 = 0 gives (s-75)(s+60) = 0. Baseline speed = 75 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 300 meters long crosses a platform of length 600 meters in 45 seconds. What is the speed of the train in km/h?
Correct Answer: Option D
Explanation:
Total distance = 300 + 600 = 900 meters. Speed = 900 / 45 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
Total distance = 300 + 600 = 900 meters. Speed = 900 / 45 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train is 120 meters, in what time will they cross each other traveling in opposite directions?
Correct Answer: Option A
Explanation:
Speed of first train = 120 / 10 = 12 m/s. Speed of second train = 120 / 15 = 8 m/s. Total distance to cross each other = 120 + 120 = 240 meters. Relative speed in opposite directions = 12 + 8 = 20 m/s. Time = 240 / 20 = 12 seconds.
Speed of first train = 120 / 10 = 12 m/s. Speed of second train = 120 / 15 = 8 m/s. Total distance to cross each other = 120 + 120 = 240 meters. Relative speed in opposite directions = 12 + 8 = 20 m/s. Time = 240 / 20 = 12 seconds.
This question belongs to:
Maths
Time Speed and Distance
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