A person walks from his home to his office at 5 km/h and reaches 10 minutes late. If he walks at 6 km/h, he reaches 2 minutes late. Find the distance. MCQ with Answer and Explanation

Question Report Error

A person walks from his home to his office at 5 km/h and reaches 10 minutes late. If he walks at 6 km/h, he reaches 2 minutes late. Find the distance.

A. 3.5 km

B. 4.0 km

C. 4.5 km

D. 5.0 km

Answer: Option B

Solution (By JKExamLibrary)

Time difference = 10 - 2 = 8 minutes = 8/60 = 2/15 hour. Let distance be d. d / 5 - d / 6 = 2/15 => d / 30 = 2/15 => d = 4 km.

This question belongs to: Maths Time Speed and Distance

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1 Report Error

A train running at 72 km/h passes an active signal pole in 10 seconds. Find the length of the train.

A. 200 meters

B. 240 meters

C. 180 meters

D. 220 meters

View Answer & Solution Discuss

Correct Answer: Option A

Explanation:
Speed = 72 * (5/18) = 20 m/s. Length of train = Speed * Time = 20 * 10 = 200 meters.

This question belongs to: Maths Time Speed and Distance

Question #2 Report Error

The speeds of two running trains are in the ratio 7 : 9. Moving along parallel tracks in opposite directions, they take 4 seconds each to cross a telegraph post. Find the time taken by them to cross each other completely.

A. 4.5 seconds

B. 5 seconds

C. 4 seconds

D. 3.5 seconds

View Answer & Solution Discuss

Correct Answer: Option C

Explanation:
Let the speeds be 7x and 9x. Length of first train = 7x * 4 = 28x. Length of second train = 9x * 4 = 36x. Total distance to cross each other = 28x + 36x = 64x. Relative speed in opposite directions = 7x + 9x = 16x. Time taken = 64x / 16x = 4 seconds.

This question belongs to: Maths Time Speed and Distance