A person walks from his home to his shop at a speed of 5 km/h and arrives 6 minutes early. If he walks at 4 km/h, he arrives 6 minutes late. Find the distance between his home and shop. MCQ with Answer and Explanation
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Question #1
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A man covers 1/3rd of his journey at 20 km/h and the remaining 2/3rd at 40 km/h. If the total distance is 120 km, find the total time taken for the journey.
Correct Answer: Option D
Explanation:
First part distance = 120 / 3 = 40 km. Time1 = 40 / 20 = 2 hours. Remaining distance = 80 km. Time2 = 80 / 40 = 2 hours. Total time = 2 + 2 = 4 hours.
First part distance = 120 / 3 = 40 km. Time1 = 40 / 20 = 2 hours. Remaining distance = 80 km. Time2 = 80 / 40 = 2 hours. Total time = 2 + 2 = 4 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A vehicle covers a specific highway distance at 50 km/h. If it spikes its speed to 60 km/h, it clears the stretch 20 minutes early. Find the total distance.
Correct Answer: Option A
Explanation:
Time difference = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d / 50 - d / 60 = 1/3 => (6d - 5d) / 300 = 1/3 => d / 300 = 1/3 => d = 100 km.
Time difference = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d / 50 - d / 60 = 1/3 => (6d - 5d) / 300 = 1/3 => d / 300 = 1/3 => d = 100 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A person walks from home to school at 4 km/h and arrives 5 minutes late. If he runs at 5 km/h, he arrives 4 minutes early. Find the distance.
Correct Answer: Option C
Explanation:
Time difference = 5 - (-4) = 9 minutes = 9/60 = 0.15 hours. Let distance be d. d / 4 - d / 5 = 0.15 => d / 20 = 0.15 => d = 3 km.
Time difference = 5 - (-4) = 9 minutes = 9/60 = 0.15 hours. Let distance be d. d / 4 - d / 5 = 0.15 => d / 20 = 0.15 => d = 3 km.
This question belongs to:
Maths
Time Speed and Distance
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