A person walks from his house to office at 5 km/h and arrives 12 minutes late. If he walks at 6 km/h, he arrives 2 minutes late. Find the distance. MCQ with Answer and Explanation

A person walks from his house to office at 5 km/h and arrives 12 minutes late. If he walks at 6 km/h, he arrives 2 minutes late. Find the distance.
A. 5.5 km
B. 4.5 km
C. 6.0 km
D. 5.0 km
Answer: Option D
Solution (By JKExamLibrary)
Time difference = 12 - 2 = 10 minutes = 10/60 = 1/6 hours. Let distance be d. d / 5 - d / 6 = 1/6 => d / 30 = 1/6 => d = 5 km.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
Excluding stoppages, a bus travels at 54 km/h and including stoppages it travels at 45 km/h. How many minutes does the bus stop per hour?
A. 12 minutes
B. 8 minutes
C. 10 minutes
D. 15 minutes

Correct Answer: Option C


Explanation:
Stoppage time per hour = (54 - 45) / 54 = 9 / 54 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
If a person covers a distance of 120 km in 3 hours, find his speed in meters per second.
A. 12.50 m/s
B. 13.33 m/s
C. 11.11 m/s
D. 10.5 m/s

Correct Answer: Option C


Explanation:
Speed = 120 / 3 = 40 km/h. Converting to m/s = 40 * (5/18) = 200 / 18 = 11.11 m/s.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A thief escapes from police custody at 1:00 PM running at 45 km/h. The police discover the escape at 1:20 PM and start chasing him at 60 km/h. At what time will the police catch the thief?
A. 2:30 PM
B. 2:00 PM
C. 2:20 PM
D. 3:00 PM

Correct Answer: Option C


Explanation:
In 20 minutes (1/3 hour), the thief covers 45 * (1/3) = 15 km. Relative speed = 60 - 45 = 15 km/h. Time taken to catch = 15 / 15 = 1 hour. Catching time = 1:20 PM + 1 hour = 2:20 PM.

This question belongs to: Maths Time Speed and Distance