A projectile is launched at 30° with speed 20 m/s. Horizontal range is: (g=10 m/s²)
A. 20 m
B. 10√3 m
C. 20√3 m
D. 40 m
Answer: Option C
Solution (By JKExamLibrary)
Range R = u²sin(2θ)/g = (20)²×sin(60°)/10 = 400×(√3/2)/10 = 20√3 m. Formula applies for level ground projection. Memory tip: sin(2θ) for θ=30° is sin60°=√3/2. Standard projectile calculation frequently appearing in competitive exams with trigonometric values.
Explanation:
According to Boyle's Law, for a given mass of an ideal gas at constant temperature, the pressure is inversely proportional to its volume (P ∝ 1/V, or P1V1 = P2V2). If the volume is halved (V2 = V1/2), the pressure must double (P2 = 2P1) to keep the product constant.
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