A real estate agent drives from his house to an office at 10 km/h and arrives 12 minutes late. If he increases his speed to 15 km/h, he arrives 4 minutes early. Find the distance. MCQ with Answer and Explanation
A real estate agent drives from his house to an office at 10 km/h and arrives 12 minutes late. If he increases his speed to 15 km/h, he arrives 4 minutes early. Find the distance.
A. 6 km
B. 10 km
C. 8 km
D. 12 km
Answer: Option C
Solution (By JKExamLibrary)
Time difference = 12 - (-4) = 16 minutes = 16/60 = 4/15 hours. Let distance be d. d/10 - d/15 = 4/15 => (3d - 2d) / 30 = 4/15 => d / 30 = 4/15 => d = 8 km.
Explanation:
Let original speed be s. 240 / (s - 10) - 240 / s = 2 => 120 / (s - 10) - 120 / s = 1 => 1200 = s(s - 10). Solving s^2 - 10s - 1200 = 0 gives (s - 40)(s + 30) = 0. Since speed is positive, s = 40 km/h.
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