A runner covers a 400-meter track. The winner finishes in 40 seconds, while the runner-up takes 44 seconds. By what distance does the winner beat the runner-up? MCQ with Answer and Explanation
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Question #1
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A boatman rows 30 km downstream and 18 km upstream, taking 3 hours for each leg of the journey. Find the speed of the boat in still water.
Correct Answer: Option A
Explanation:
Downstream speed = 30 / 3 = 10 km/h. Upstream speed = 18 / 3 = 6 km/h. Speed in still water = (10 + 6) / 2 = 8 km/h.
Downstream speed = 30 / 3 = 10 km/h. Upstream speed = 18 / 3 = 6 km/h. Speed in still water = (10 + 6) / 2 = 8 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train crosses a bridge of length 150 meters in 15 seconds and a pole in 9 seconds. What is the length of the train?
Correct Answer: Option D
Explanation:
Let train length be L. Speed = L / 9. Also, Speed = (L + 150) / 15. So, L / 9 = (L + 150) / 15 => 15L = 9L + 1350 => 6L = 1350 => L = 225 meters.
Let train length be L. Speed = L / 9. Also, Speed = (L + 150) / 15. So, L / 9 = (L + 150) / 15 => 15L = 9L + 1350 => 6L = 1350 => L = 225 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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The speed index tracking profile of an express locomotive is exactly 20% higher than a commercial car. Both take off from terminal M together and reach terminal N, 120 km away, at the same instant. On the corridor route, the train logs a total stall of 10 minutes at intermediate stations. Find the car speed.
Correct Answer: Option D
Explanation:
Let car speed be c, then train tracking speed is 1.2c. Time difference parameter = 120/c - 120/(1.2c) = 10/60 hours = 1/6 hours. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
Let car speed be c, then train tracking speed is 1.2c. Time difference parameter = 120/c - 120/(1.2c) = 10/60 hours = 1/6 hours. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
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