A sedan tracks from location M to N at 50 km/h and manages the return tract to M at 70 km/h. What is the average speed recorded across the round journey? MCQ with Answer and Explanation
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Question #1
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A train 110 meters long passing a platform 290 meters long requires exactly 20 seconds. What is the speed of the train in km/h?
Correct Answer: Option A
Explanation:
Total distance = 110 + 290 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
Total distance = 110 + 290 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car covers a distance of 120 km at 30 km/h and another 120 km at 50 km/h. Find the total time spent during the journey.
Correct Answer: Option D
Explanation:
Time for first part = 120 / 30 = 4 hours. Time for second part = 120 / 50 = 2.4 hours. Total time taken = 4 + 2.4 = 6.4 hours.
Time for first part = 120 / 30 = 4 hours. Time for second part = 120 / 50 = 2.4 hours. Total time taken = 4 + 2.4 = 6.4 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train passes a platform 110 meters long in 40 seconds and a boy standing on the platform in 30 seconds. Find the length of the train.
Correct Answer: Option B
Explanation:
Let length of train be L. Speed = L/30. Also, Speed = (L+110)/40. So L/30 = (L+110)/40 => 4L = 3L + 330 => L = 330 meters.
Let length of train be L. Speed = L/30. Also, Speed = (L+110)/40. So L/30 = (L+110)/40 => 4L = 3L + 330 => L = 330 meters.
This question belongs to:
Maths
Time Speed and Distance
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