A sprinter tracks a 100-meter course in 10 seconds, while the runner-up completes it in 11 seconds. By what distance does the winner beat the runner-up? MCQ with Answer and Explanation

A sprinter tracks a 100-meter course in 10 seconds, while the runner-up completes it in 11 seconds. By what distance does the winner beat the runner-up?
A. 8.50 meters
B. 9.50 meters
C. 9.09 meters
D. 10.00 meters
Answer: Option C
Solution (By JKExamLibrary)
Speed of runner-up = 100 / 11 m/s. Distance covered by runner-up in 10 seconds = (100 / 11) * 10 = 1000 / 11 = 90.91 meters. Margin = 100 - 90.91 = 9.09 meters.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A car climbs a hill at 24 km/h and descends the same hill at 36 km/h. Find the average speed of the car for the entire journey.
A. 33.2 km/h
B. 28.8 km/h
C. 30 km/h
D. 32 km/h

Correct Answer: Option B


Explanation:
Average Speed = (2 * 24 * 36) / (24 + 36) = 1728 / 60 = 28.8 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A jogger covers a distance of 18 km in 2 hours. If he runs at 1.5 times his original speed, how much time will he take to cover a distance of 27 km?
A. 2 hours
B. 2.5 hours
C. 1.5 hours
D. 3 hours

Correct Answer: Option A


Explanation:
Original speed = 18 / 2 = 9 km/h. New speed = 1.5 * 9 = 13.5 km/h. Time needed for 27 km = 27 / 13.5 = 2 hours.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A private sedan tracks a sector path length of 480 km in 5 hours 20 minutes. Find its mean average speed index.
A. 100 km/h
B. 95 km/h
C. 85 km/h
D. 90 km/h

Correct Answer: Option D


Explanation:
Time = 5 hours 20 minutes = 5 + 20/60 = 5.333 hours = 16/3 hours. Speed index = Sector Distance / Time = 480 / (16/3) = 480 * 3 / 16 = 30 * 3 = 90 km/h.

This question belongs to: Maths Time Speed and Distance