A student covers the distance from his house to school at 5 km/h and arrives 8 minutes late. The next day, he walks at 6 km/h and arrives 2 minutes early. Find the distance between his house and the school. MCQ with Answer and Explanation
A student covers the distance from his house to school at 5 km/h and arrives 8 minutes late. The next day, he walks at 6 km/h and arrives 2 minutes early. Find the distance between his house and the school.
A. 4 km
B. 6 km
C. 8 km
D. 5 km
Answer: Option D
Solution (By JKExamLibrary)
Time difference = 8 - (-2) = 10 minutes = 1/6 hour. Let distance be d. d/5 - d/6 = 1/6 => d/30 = 1/6 => d = 5 km.
Explanation:
When A covers 1000m, B covers 900m. When B covers 1000m, C covers 900m. So when B covers 900m, C covers 900 * (900/1000) = 810m. Therefore, when A covers 1000m, C covers 810m. A beats C by 1000 - 810 = 190m.
A person walks from his villa to a local station at 4 km/h and arrives 10 minutes late. If he routes at 5 km/h, he arrives 2 minutes early. Find the distance.
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