A student walking at 3 km/h reaches his school 15 minutes late. If he walks at 4 km/h, he reaches 15 minutes early. Find the distance. MCQ with Answer and Explanation

A student walking at 3 km/h reaches his school 15 minutes late. If he walks at 4 km/h, he reaches 15 minutes early. Find the distance.
A. 4 km
B. 5 km
C. 8 km
D. 6 km
Answer: Option D
Solution (By JKExamLibrary)
Time difference = 15 - (-15) = 30 minutes = 0.5 hours. Let distance be d. d/3 - d/4 = 0.5 => d/12 = 0.5 => d = 6 km.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
The ratio between the speeds of two trains is 7:8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
A. 75 km/h
B. 70 km/h
C. 84 km/h
D. 87.5 km/h

Correct Answer: Option D


Explanation:
Speed of second train = 400 / 4 = 100 km/h. Ratio is 7:8, so 8 parts = 100 km/h. 1 part = 12.5 km/h. First train speed = 7 parts = 7 * 12.5 = 87.5 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A passenger train 180 meters long is running at 60 km/h. How much time will it take to pass a platform of length 220 meters?
A. 24 seconds
B. 30 seconds
C. 27 seconds
D. 20 seconds

Correct Answer: Option A


Explanation:
Total distance = 180 + 220 = 400 meters. Speed = 60 * (5/18) = 50/3 m/s. Time = 400 / (50/3) = 400 * 3 / 50 = 24 seconds.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A traveler accounts 30% of his route stretch at 15 km/h and the left over 70% at 35 km/h. Find his baseline average speed across the course.
A. 25.0 km/h
B. 24.5 km/h
C. 26.25 km/h
D. 28.00 km/h

Correct Answer: Option A


Explanation:
Let total distance be 100 km. First segment = 30 km; Time = 30 / 15 = 2 hours. Second segment = 70 km; Time = 70 / 35 = 2 hours. Total distance = 100 km, Total time = 4 hours. Average speed = 100 / 4 = 25 km/h.

This question belongs to: Maths Time Speed and Distance