A student walks from his quarter block to the academy center at 4 km/h and arrives 8 minutes late. If he manages a pace of 5 km/h, he arrives 4 minutes early. Find the track distance. MCQ with Answer and Explanation

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A student walks from his quarter block to the academy center at 4 km/h and arrives 8 minutes late. If he manages a pace of 5 km/h, he arrives 4 minutes early. Find the track distance.

A. 4.0 km

B. 5.0 km

C. 3.5 km

D. 4.5 km

Answer: Option A

Solution (By JKExamLibrary)

Time difference = 8 - (-4) = 12 minutes = 10/60 = 1/5 hours. Let distance be d. d/4 - d/5 = 1/5 => d/20 = 1/5 => d = 4 km.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error

A person covers a distance of 120 km at 30 km/h and another 80 km at 40 km/h. Find his average speed for the full journey.

A. 33.33 km/h

B. 35.0 km/h

C. 34.5 km/h

D. 32.2 km/h

View Answer & Solution Discuss

Correct Answer: Option A

Explanation:
Total distance = 120 + 80 = 200 km. Time 1 = 120 / 30 = 4 hours. Time 2 = 80 / 40 = 2 hours. Total time = 6 hours. Average speed = 200 / 6 = 33.33 km/h.

This question belongs to: Maths Time Speed and Distance

Question #2 Report Error

Two trains start from stations A and B and travel towards each other at speeds of 50 km/h and 60 km/h respectively. At the time of their meeting, the second train has traveled 120 km more than the first. Find the distance between A and B.

A. 1320 km

B. 1500 km

C. 1200 km

D. 1440 km

View Answer & Solution Discuss

Correct Answer: Option A

Explanation:
Let the time they travel before meeting be t hours. Distance difference = 60t - 50t = 10t = 120 km => t = 12 hours. Total distance = (50 + 60) * t = 110 * 12 = 1320 km.

This question belongs to: Maths Time Speed and Distance