A sum of money at compound interest amounts to Rs. 1352 in 2 years and Rs. 1406.08 in 3 years. Find the sum. MCQ with Answer and Explanation

A sum of money at compound interest amounts to Rs. 1352 in 2 years and Rs. 1406.08 in 3 years. Find the sum.
A. Rs. 1250
B. Rs. 1200
C. Rs. 1300
D. Rs. 1350
Answer: Option A
Solution (By JKExamLibrary)
Rate = (1406.08/1352 − 1)×100 = 4%. P = 1352 / (1.04)² = 1352 / 1.0816 = 1250.

This question belongs to: Maths Compound Interest

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Compound Interest Questions

Question #1 Report Error
What is the compound interest on Rs. 20000 for 1 year at 16% per annum, compounded half-yearly?
A. Rs. 3200
B. Rs. 3328
C. Rs. 3500
D. Rs. 3400

Correct Answer: Option B


Explanation:
Half-yearly rate = 16/2 = 8%. Time = 2 half-years. Amount = 20000 * (1 + 8/100)^2 = 20000 * 1.1664 = Rs. 23328. Compound Interest = 23328 - 20000 = Rs. 3328.

This question belongs to: Maths Compound Interest
Question #2 Report Error
Find the compound interest on Rs. 8500 at 8% per annum for 2 years.
A. Rs. 1420
B. Rs. 1414.40
C. Rs. 1430
D. Rs. 1440

Correct Answer: Option B


Explanation:
A = 8500 × (1.08)² = 8500 × 1.1664 = 9914.40, CI = 9914.40 − 8500 = Rs. 1414.40.

This question belongs to: Maths Compound Interest
Question #3 Report Error
The difference between simple interest and compound interest on a certain sum of money for 2 years at 4% per annum is Rs. 64. Find the sum.
A. Rs. 36000
B. Rs. 44000
C. Rs. 48000
D. Rs. 40000

Correct Answer: Option D


Explanation:
Difference for 2 years = P * (R/100)^2 => 64 = P * (4/100)^2 => 64 = P * (16 / 10000) => P = (64 * 10000) / 16 = Rs. 40000.

This question belongs to: Maths Compound Interest