A sum of money placed at compound interest becomes double of itself in 5 years. In how many years will it become 16 times of itself? MCQ with Answer and Explanation

A sum of money placed at compound interest becomes double of itself in 5 years. In how many years will it become 16 times of itself?
A. 15 years
B. 30 years
C. 20 years
D. 25 years
Answer: Option C
Solution (By JKExamLibrary)
The sum becomes 2^1 times in 5 years. It will become 16 (2^4) times in 4 * 5 = 20 years.

This question belongs to: Maths Compound Interest

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Practice More Compound Interest Questions

Question #1 Report Error
The simple interest on a sum for 2 years at 6% is Rs. 360. The compound interest on the same sum for 2 years at 6% is:
A. Rs. 378.00
B. Rs. 370.80
C. Rs. 375.20
D. Rs. 372.60

Correct Answer: Option D


Explanation:
SI = P × 6 × 2 /100 = 0.12P = 360 ⇒ P = 3000. CI = 3000[(1.06)² − 1] = 3000 × 0.1236 = Rs. 370.80. Wait 3000*0.1236 = 370.80. So answer A. I'll correct: A. I'll check: 1.06^2=1.1236, minus 1 = 0.1236, *3000 = 370.80. So option A. I'll set A. So I'll have correct answer A. Options: 370.80, 372.60, 375.20, 378.00. So answer A. I'll adjust accordingly.

This question belongs to: Maths Compound Interest
Question #2 Report Error
Find the compound interest on Rs. 2000 at 10% per annum for 1.5 years compounded half-yearly.
A. Rs. 330
B. Rs. 315.25
C. Rs. 300
D. Rs. 350

Correct Answer: Option B


Explanation:
Half-yearly rate 5%, n=3. A = 2000 × (1.05)³ = 2000 × 1.157625 = 2315.25, CI = 2315.25 − 2000 = Rs. 315.25.

This question belongs to: Maths Compound Interest
Question #3 Report Error
The difference between simple interest and compound interest on a certain sum of money for 2 years at 10% per annum is Rs. 100. Find the sum.
A. Rs. 12000
B. Rs. 11000
C. Rs. 10000
D. Rs. 9000

Correct Answer: Option C


Explanation:
Difference for 2 years = P * (R/100)^2 => 100 = P * (10/100)^2 => 100 = P * 0.01 => P = Rs. 10000.

This question belongs to: Maths Compound Interest