A sum of money placed at compound interest becomes double of itself in 8 years. In how many years will it become 16 times of itself? MCQ with Answer and Explanation

A sum of money placed at compound interest becomes double of itself in 8 years. In how many years will it become 16 times of itself?
A. 24 years
B. 40 years
C. 48 years
D. 32 years
Answer: Option D
Solution (By JKExamLibrary)
The sum becomes 2^1 times in 8 years. It will become 16 (2^4) times in 4 * 8 = 32 years.

This question belongs to: Maths Compound Interest

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Practice More Compound Interest Questions

Question #1 Report Error
The compound interest on Rs. 8000 at 10% per annum for 1 year compounded half-yearly is:
A. Rs. 820
B. Rs. 800
C. Rs. 860
D. Rs. 840

Correct Answer: Option A


Explanation:
Half-yearly rate 5%, n=2. A = 8000 × (1.05)² = 8000 × 1.1025 = 8820, CI = 8820 − 8000 = Rs. 820.

This question belongs to: Maths Compound Interest
Question #2 Report Error
A sum of money at compound interest doubles in 4 years. In how many years will it become 8 times?
A. 16 years
B. 12 years
C. 10 years
D. 20 years

Correct Answer: Option B


Explanation:
2 times in 4 years, 8 = 2³ ⇒ 4 × 3 = 12 years.

This question belongs to: Maths Compound Interest
Question #3 Report Error
The compound interest on a certain sum for 2 years at 10% per annum is Rs. 420. What would be the simple interest on the same sum at the same rate for the same time?
A. Rs. 410
B. Rs. 390
C. Rs. 380
D. Rs. 400

Correct Answer: Option D


Explanation:
For 2 years at 10%, effective compound interest rate is 10 + 10 + (1010)/100 = 21%. Effective simple interest rate is 10 * 2 = 20%. Given 21% of sum = 420, then 1% of sum = 20. Simple Interest = 20% of sum = 20 * 20 = Rs. 400.

This question belongs to: Maths Compound Interest