A thief escapes at 5:00 AM at 40 km/h. The police pursue him starting at 6:00 AM at 50 km/h. At what time will the thief be apprehended? MCQ with Answer and Explanation

A thief escapes at 5:00 AM at 40 km/h. The police pursue him starting at 6:00 AM at 50 km/h. At what time will the thief be apprehended?
A. 10:00 AM
B. 9:30 AM
C. 10:30 AM
D. 11:00 AM
Answer: Option A
Solution (By JKExamLibrary)
By 6:00 AM, the thief has traveled for 1 hour and covered 40 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 40 / 10 = 4 hours. Capture time = 6:00 AM + 4 hours = 10:00 AM.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A private sedan tracks a sector path length of 480 km in 5 hours 20 minutes. Find its mean average speed index.
A. 100 km/h
B. 85 km/h
C. 95 km/h
D. 90 km/h

Correct Answer: Option D


Explanation:
Time = 5 hours 20 minutes = 5 + 20/60 = 5.333 hours = 16/3 hours. Speed index = Sector Distance / Time = 480 / (16/3) = 480 * 3 / 16 = 30 * 3 = 90 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A cyclist covers 1200 meters in 4 minutes flat. Find his speed index in km/h.
A. 15 km/h
B. 18 km/h
C. 20 km/h
D. 22 km/h

Correct Answer: Option B


Explanation:
Time = 4 minutes = 240 seconds. Speed = 1200 / 240 = 5 m/s. Converting to km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
Walking at 4/5 of his normal pace, an official is 12 minutes late to his assignment station. Find his usual baseline time.
A. 44 minutes
B. 48 minutes
C. 56 minutes
D. 52 minutes

Correct Answer: Option B


Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 12 minutes. Usual time = 12 * 4 = 48 minutes.

This question belongs to: Maths Time Speed and Distance