A thief escapes at 5:00 AM at 40 km/h. The police pursue him starting at 6:00 AM at 50 km/h. At what time will the thief be apprehended? MCQ with Answer and Explanation
A thief escapes at 5:00 AM at 40 km/h. The police pursue him starting at 6:00 AM at 50 km/h. At what time will the thief be apprehended?
A. 10:00 AM
B. 9:30 AM
C. 10:30 AM
D. 11:00 AM
Answer: Option A
Solution (By JKExamLibrary)
By 6:00 AM, the thief has traveled for 1 hour and covered 40 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 40 / 10 = 4 hours. Capture time = 6:00 AM + 4 hours = 10:00 AM.
Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 12 minutes. Usual time = 12 * 4 = 48 minutes.
No comments yet. Be the first to start the discussion!