A track sprinter matches a 300-meter straight heat in 30 seconds. Find his moving speed in km/h. MCQ with Answer and Explanation
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Question #1
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A local train spans a track sector in 40 minutes. If its speed is lowered by 6 km/h, it tracks the same sector in 45 minutes. Find the distance of this track sector.
Correct Answer: Option A
Explanation:
Let original speed be s. s * (40/60) = (s - 6) * (45/60) => 40s = 45s - 270 => 5s = 270 => s = 54 km/h. Distance = 54 * (40/60) = 36 km.
Let original speed be s. s * (40/60) = (s - 6) * (45/60) => 40s = 45s - 270 => 5s = 270 => s = 54 km/h. Distance = 54 * (40/60) = 36 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A baseline boat hull can row 10 km/h in still water. If the river current tracks a velocity of 2 km/h, find the exact sector distance covered downstream by the boat hull in 30 minutes flat.
Correct Answer: Option B
Explanation:
Downstream speed = 10 + 2 = 12 km/h. Time = 30 minutes = 0.5 hour. Distance covered = Speed * Time = 12 * 0.5 = 6 km.
Downstream speed = 10 + 2 = 12 km/h. Time = 30 minutes = 0.5 hour. Distance covered = Speed * Time = 12 * 0.5 = 6 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A boatman rows 30 km downstream and 18 km upstream, taking 3 hours for each leg of the journey. Find the speed of the boat in still water.
Correct Answer: Option A
Explanation:
Downstream speed = 30 / 3 = 10 km/h. Upstream speed = 18 / 3 = 6 km/h. Speed in still water = (10 + 6) / 2 = 8 km/h.
Downstream speed = 30 / 3 = 10 km/h. Upstream speed = 18 / 3 = 6 km/h. Speed in still water = (10 + 6) / 2 = 8 km/h.
This question belongs to:
Maths
Time Speed and Distance
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