A train 100 meters long passes an extension platform 300 meters long in 20 seconds. What is the speed of the train in km/h? MCQ with Answer and Explanation
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Question #1
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A car covers a total loop distance of 300 km. If the baseline speed is raised by 10 km/h, the trip takes 1 hour less. Find the original speed.
Correct Answer: Option D
Explanation:
Let original speed be s. 300/s - 300/(s+10) = 1 => 3000 = s(s+10). Solving s^2 + 10s - 3000 = 0 yields (s-50)(s+60) = 0. Speed = 50 km/h.
Let original speed be s. 300/s - 300/(s+10) = 1 => 3000 = s(s+10). Solving s^2 + 10s - 3000 = 0 yields (s-50)(s+60) = 0. Speed = 50 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 120 meters long passes a track worker walking at 6 km/h in the same direction in 12 seconds. What is the actual speed of the train?
Correct Answer: Option D
Explanation:
Relative speed = 120 / 12 = 10 m/s = 10 * (18/5) = 36 km/h. Since they move in the same direction, Relative Speed = Speed of train - Speed of worker => 36 = Speed of train - 6 => Speed of train = 42 km/h.
Relative speed = 120 / 12 = 10 m/s = 10 * (18/5) = 36 km/h. Since they move in the same direction, Relative Speed = Speed of train - Speed of worker => 36 = Speed of train - 6 => Speed of train = 42 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train 120 meters long is running at a speed of 54 km/h. How long will it take to cross a platform 180 meters long?
Correct Answer: Option B
Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Total distance = 120 + 180 = 300 meters. Time taken = 300 / 15 = 20 seconds.
Speed of train = 54 * (5/18) = 15 m/s. Total distance = 120 + 180 = 300 meters. Time taken = 300 / 15 = 20 seconds.
This question belongs to:
Maths
Time Speed and Distance
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