A train 150 meters long is traveling at a speed of 45 km/h. How much time will it take to clear a platform 300 meters long? MCQ with Answer and Explanation
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Question #1
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A person runs around a circular track of circumference 500 meters. If his speed is 18 km/h, how many rounds can he complete in 10 minutes?
Correct Answer: Option D
Explanation:
Speed = 18 km/h = 5 m/s. Time = 10 minutes = 600 seconds. Total distance = 5 * 600 = 3000 meters. Number of rounds = 3000 / 500 = 6 rounds.
Speed = 18 km/h = 5 m/s. Time = 10 minutes = 600 seconds. Total distance = 5 * 600 = 3000 meters. Number of rounds = 3000 / 500 = 6 rounds.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Walking at 5/7 of his usual speed, a man reaches his destination 24 minutes late. What is his usual time?
Correct Answer: Option D
Explanation:
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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Two passenger trains of equal layout lengths cross a station pole in 15 seconds and 30 seconds respectively. If each train length measures 150 meters, find the time parameter required to pass each other completely when tracking in opposite directions.
Correct Answer: Option D
Explanation:
Speed of first train = 150 / 15 = 10 m/s. Speed of second train = 150 / 30 = 5 m/s. Total passing distance = 150 + 150 = 300 meters. Relative speed in opposite directions = 10 + 5 = 15 m/s. Time required = 300 / 15 = 20 seconds.
Speed of first train = 150 / 15 = 10 m/s. Speed of second train = 150 / 30 = 5 m/s. Total passing distance = 150 + 150 = 300 meters. Relative speed in opposite directions = 10 + 5 = 15 m/s. Time required = 300 / 15 = 20 seconds.
This question belongs to:
Maths
Time Speed and Distance
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