A train 160 meters long passes a standing man in 8 seconds. What is the speed of the train? MCQ with Answer and Explanation
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Question #1
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A man covers 50 km at a speed of 25 km/h and another 90 km at a speed of 30 km/h. Find his average speed for the whole journey.
Correct Answer: Option B
Explanation:
Total distance = 50 + 90 = 140 km. Time for first part = 50 / 25 = 2 hours. Time for second part = 90 / 30 = 3 hours. Total time = 5 hours. Average speed = 140 / 5 = 28 km/h.
Total distance = 50 + 90 = 140 km. Time for first part = 50 / 25 = 2 hours. Time for second part = 90 / 30 = 3 hours. Total time = 5 hours. Average speed = 140 / 5 = 28 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Two sprinters race on a 200-meter straight track. The ratio of their speeds is 4 : 5. When the winner crosses the finish line, how far away from the tape is the slower sprinter?
Correct Answer: Option B
Explanation:
The faster sprinter covers 5 parts = 200 meters, so 1 part = 40 meters. In that same timeframe, the slower sprinter covers 4 parts = 4 * 40 = 160 meters. Distance remaining for the slower sprinter = 200 - 160 = 40 meters.
The faster sprinter covers 5 parts = 200 meters, so 1 part = 40 meters. In that same timeframe, the slower sprinter covers 4 parts = 4 * 40 = 160 meters. Distance remaining for the slower sprinter = 200 - 160 = 40 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train passes a 110-meter long bridge in 12 seconds and a standard sign post in 7 seconds. Find the length of the train.
Correct Answer: Option A
Explanation:
Time taken to cross the bridge alone = 12 - 7 = 5 seconds. Speed of train = 110 / 5 = 22 m/s. Length of train = Speed * Time to cross sign post = 22 * 7 = 154 meters.
Time taken to cross the bridge alone = 12 - 7 = 5 seconds. Speed of train = 110 / 5 = 22 m/s. Length of train = Speed * Time to cross sign post = 22 * 7 = 154 meters.
This question belongs to:
Maths
Time Speed and Distance
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