A train 180 meters long running at 54 km/h passes a stationary point tracking observer. Find the time parameter required to cross. MCQ with Answer and Explanation

A train 180 meters long running at 54 km/h passes a stationary point tracking observer. Find the time parameter required to cross.
A. 12 seconds
B. 14 seconds
C. 10 seconds
D. 16 seconds
Answer: Option A
Solution (By JKExamLibrary)
Speed of train = 54 * (5/18) = 15 m/s. Time taken = 180 / 15 = 12 seconds.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A person row a boat 45 km downstream in 3 hours and manages the return journey upstream in 9 hours. Find the speed of the river current.
A. 5.5 km/h
B. 6.0 km/h
C. 4.5 km/h
D. 5.0 km/h

Correct Answer: Option D


Explanation:
Downstream speed = 45 / 3 = 15 km/h. Upstream speed = 45 / 9 = 5 km/h. Speed of current = (15 - 5) / 2 = 10 / 2 = 5 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A sound wave travels at a speed of 340 m/s. Find the distance covered by the wave in 10 seconds.
A. 3.8 km
B. 3.2 km
C. 3.4 km
D. 3.6 km

Correct Answer: Option C


Explanation:
Distance = Speed * Time = 340 * 10 = 3400 meters = 3.4 km.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
Excluding stoppages, the speed of a train is 80 km/h and including stoppages, it is 60 km/h. For how many minutes does the train stop per hour?
A. 15 minutes
B. 12 minutes
C. 18 minutes
D. 20 minutes

Correct Answer: Option A


Explanation:
Stoppage time per hour = (Fast speed - Slow speed) / Fast speed = (80 - 60) / 80 = 20 / 80 = 1/4 hour. Converting to minutes = (1/4) * 60 = 15 minutes.

This question belongs to: Maths Time Speed and Distance