A train 200 meters long passes a running man in 10 seconds when both move in the same direction. If the speed of the man is 6 km/h, find the speed of the train. MCQ with Answer and Explanation
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Question #1
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A train passes a standing man in 6 seconds and a 210-meter long platform in 16 seconds. Find the speed of the train.
Correct Answer: Option A
Explanation:
Let length of train be L. Speed = L/6. Also, Speed = (L + 210)/16. Equating them: L/6 = (L+210)/16 => 16L = 6L + 1260 => 10L = 1260 => L = 126 meters. Speed = 126 / 6 = 21 m/s. Speed in km/h = 21 * (18/5) = 378 / 5 = 75.6 km/h.
Let length of train be L. Speed = L/6. Also, Speed = (L + 210)/16. Equating them: L/6 = (L+210)/16 => 16L = 6L + 1260 => 10L = 1260 => L = 126 meters. Speed = 126 / 6 = 21 m/s. Speed in km/h = 21 * (18/5) = 378 / 5 = 75.6 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A boatman rows 15 km downstream in 3 hours and 12 km upstream in 4 hours. What is the speed of the boat in still water?
Correct Answer: Option B
Explanation:
Downstream speed = 15 / 3 = 5 km/h. Upstream speed = 12 / 4 = 3 km/h. Speed in still water = (5 + 3) / 2 = 4 km/h.
Downstream speed = 15 / 3 = 5 km/h. Upstream speed = 12 / 4 = 3 km/h. Speed in still water = (5 + 3) / 2 = 4 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A person runs around a square track of side 60 meters. If his speed is 12 km/h, how much time does he take to complete one round?
Correct Answer: Option D
Explanation:
Perimeter of the track = 4 * 60 = 240 meters. Speed = 12 km/h = 12 * (5/18) = 10/3 m/s. Time required = Distance / Speed = 240 / (10/3) = 240 * 3 / 10 = 72 seconds.
Perimeter of the track = 4 * 60 = 240 meters. Speed = 12 km/h = 12 * (5/18) = 10/3 m/s. Time required = Distance / Speed = 240 / (10/3) = 240 * 3 / 10 = 72 seconds.
This question belongs to:
Maths
Time Speed and Distance
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