A train covers a distance between two stations in 45 minutes. If its speed is reduced by 5 km/h, it covers the same distance in 48 minutes. Find the distance between the two stations. MCQ with Answer and Explanation
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Question #1
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A person walking at 4/5 of his usual speed reaches his shop 15 minutes late. What is his usual time to reach the shop?
Correct Answer: Option C
Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 15 minutes. Usual time = 15 * 4 = 60 minutes.
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 15 minutes. Usual time = 15 * 4 = 60 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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If a student walks from his house to school at 5 km/h, he is late by 10 minutes. However, if he walks at 6 km/h, he is late by only 2 minutes. Find the distance between his house and school.
Correct Answer: Option B
Explanation:
Time difference = 10 - 2 = 8 minutes = 8/60 hour = 2/15 hour. Let distance be d. d/5 - d/6 = 2/15 => d/30 = 2/15 => d = 60/15 = 4 km.
Time difference = 10 - 2 = 8 minutes = 8/60 hour = 2/15 hour. Let distance be d. d/5 - d/6 = 2/15 => d/30 = 2/15 => d = 60/15 = 4 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train 150 meters long takes 20 seconds to cross a platform 250 meters long. Find the speed of the train in km/h.
Correct Answer: Option A
Explanation:
Total distance = 150 + 250 = 400 meters. Time = 20 seconds. Speed = 400 / 20 = 20 m/s. Speed in km/h = 20 * (18/5) = 72 km/h.
Total distance = 150 + 250 = 400 meters. Time = 20 seconds. Speed = 400 / 20 = 20 m/s. Speed in km/h = 20 * (18/5) = 72 km/h.
This question belongs to:
Maths
Time Speed and Distance
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