A train passes a pedestrian standing on a platform in 8 seconds and passes the platform itself, which is 200 meters long, in 18 seconds. Find the speed of the train in km/h. MCQ with Answer and Explanation

A train passes a pedestrian standing on a platform in 8 seconds and passes the platform itself, which is 200 meters long, in 18 seconds. Find the speed of the train in km/h.
A. 84 km/h
B. 80 km/h
C. 72 km/h
D. 64 km/h
Answer: Option C
Solution (By JKExamLibrary)
Time taken to cross the platform alone = 18 - 8 = 10 seconds. Speed of train = 200 / 10 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A thief is spotted by a policeman from a distance of 250 meters. The thief runs at 11 km/h and the policeman chases him at 13 km/h. Find the distance covered by the thief before he is caught.
A. 1250 meters
B. 1375 meters
C. 1625 meters
D. 1500 meters

Correct Answer: Option B


Explanation:
Relative speed = 13 - 11 = 2 km/h. Time to catch the thief = 0.25 km / 2 km/h = 0.125 hours. Distance covered by thief = Speed * Time = 11 km/h * 0.125 hours = 1.375 km = 1375 meters.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A train 200 meters long passes a static utility pole in 10 seconds. Find the time it takes to completely pass a platform of length 400 meters.
A. 26 seconds
B. 32 seconds
C. 30 seconds
D. 35 seconds

Correct Answer: Option C


Explanation:
Speed of train = 200 / 10 = 20 m/s. Total distance to pass platform = 200 + 400 = 600 meters. Time taken = 600 / 20 = 30 seconds.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A passenger coach locomotive 200 meters long passes a clear roadside post marker in 10 seconds flat. Find the time needed to cross an extensions platform 440 meters long.
A. 32 seconds
B. 28 seconds
C. 36 seconds
D. 40 seconds

Correct Answer: Option A


Explanation:
Speed of coach locomotive = 200 / 10 = 20 m/s. Total distance to clear platform stretch = 200 + 440 = 640 meters. Time required = 640 / 20 = 32 seconds.

This question belongs to: Maths Time Speed and Distance