A train passes a standing passenger in 8 seconds and crosses a 180-meter long platform in 17 seconds. Find the speed of the train. MCQ with Answer and Explanation
Question
Report Error
Discuss this Question (0)
Practice More Time Speed and Distance Questions
Question #1
Report Error
A car covers a distance of 450 km at a certain speed. If the speed is increased by 5 km/h, it takes 1 hour less to cover the same distance. Find the original speed of the car.
Correct Answer: Option C
Explanation:
Let original speed be s. 450/s - 450/(s+5) = 1 => 450(s + 5 - s) = s(s + 5) => 2250 = s(s + 5). Solving s^2 + 5s - 2250 = 0 gives (s - 45)(s + 50) = 0. Since speed is positive, s = 45 km/h.
Let original speed be s. 450/s - 450/(s+5) = 1 => 450(s + 5 - s) = s(s + 5) => 2250 = s(s + 5). Solving s^2 + 5s - 2250 = 0 gives (s - 45)(s + 50) = 0. Since speed is positive, s = 45 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
Report Error
A boat moves upstream at a pace of 10 km/h and handles downstream at 16 km/h. Find the speed of the river current.
Correct Answer: Option A
Explanation:
Speed of river current = (Downstream speed - Upstream speed) / 2 = (16 - 10) / 2 = 6 / 2 = 3 km/h.
Speed of river current = (Downstream speed - Upstream speed) / 2 = (16 - 10) / 2 = 6 / 2 = 3 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
Report Error
A person travels a distance of 120 km at 40 km/h and returns at 60 km/h. Find the total time spent for the entire round trip.
Correct Answer: Option B
Explanation:
Time for onward journey = 120 / 40 = 3 hours. Time for return journey = 120 / 60 = 2 hours. Total time = 3 + 2 = 5 hours.
Time for onward journey = 120 / 40 = 3 hours. Time for return journey = 120 / 60 = 2 hours. Total time = 3 + 2 = 5 hours.
This question belongs to:
Maths
Time Speed and Distance
No comments yet. Be the first to start the discussion!