A train traveling at 72 km/h crosses a platform 160 meters long in 18 seconds. Find the length of the train. MCQ with Answer and Explanation

A train traveling at 72 km/h crosses a platform 160 meters long in 18 seconds. Find the length of the train.
A. 180 meters
B. 200 meters
C. 220 meters
D. 240 meters
Answer: Option B
Solution (By JKExamLibrary)
Speed = 72 * (5/18) = 20 m/s. Total distance in 18 seconds = 20 * 18 = 360 meters. Train length + Platform length = 360 => Train length + 160 = 360 => Train length = 200 meters.

This question belongs to: Maths Time Speed and Distance

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time Speed and Distance Questions

Question #1 Report Error
A train passes a static observer in 6 seconds and a platform 160 meters long in 14 seconds. Find the length of the train.
A. 100 meters
B. 150 meters
C. 140 meters
D. 120 meters

Correct Answer: Option D


Explanation:
Time to cross the platform distance alone = 14 - 6 = 8 seconds. Speed of train = 160 / 8 = 20 m/s. Length of train = Speed * Time to pass observer = 20 * 6 = 120 meters.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A car tracks a total segment of 360 km. If the uniform speed is boosted by 15 km/h, it covers the course in 4 hours flat. Find the original speed.
A. 70 km/h
B. 85 km/h
C. 80 km/h
D. 75 km/h

Correct Answer: Option D


Explanation:
New speed = 360 / 4 = 90 km/h. Since the new speed is 15 km/h faster than original speed, original speed = 90 - 15 = 75 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A sprinter tracks a 400-meter oval dash stretch in 44 seconds. Find his approximate pace in km/h.
A. 32.7 km/h
B. 36.0 km/h
C. 34.2 km/h
D. 30.5 km/h

Correct Answer: Option A


Explanation:
Speed = 400 / 44 m/s = 100 / 11 m/s. In km/h = (100 / 11) * (18/5) = 360 / 11 = 32.72 km/h.

This question belongs to: Maths Time Speed and Distance