If a delivery agent cycles at 15 km/h instead of 11 km/h, he travels 20 km more in the same allotted duration. Find the actual distance covered by him at his lower speed. MCQ with Answer and Explanation
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Question #1
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An athlete loops a regular hexagonal field of side 50 meters. If his speed is 15 km/h, find the time taken to complete one full lap.
Correct Answer: Option B
Explanation:
Perimeter of the hexagonal field = 6 * 50 = 300 meters. Speed = 15 km/h = 15 * (5/18) = 25/6 m/s. Time = Distance / Speed = 300 / (25/6) = 300 * 6 / 25 = 12 * 6 = 72 seconds.
Perimeter of the hexagonal field = 6 * 50 = 300 meters. Speed = 15 km/h = 15 * (5/18) = 25/6 m/s. Time = Distance / Speed = 300 / (25/6) = 300 * 6 / 25 = 12 * 6 = 72 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train running at 60 km/h crosses a bridge 200 meters long in 24 seconds. Find the length of the train.
Correct Answer: Option A
Explanation:
Speed = 60 * (5/18) = 50/3 m/s. Total distance in 24 seconds = (50/3) * 24 = 400 meters. Length of train = 400 - 200 = 200 meters.
Speed = 60 * (5/18) = 50/3 m/s. Total distance in 24 seconds = (50/3) * 24 = 400 meters. Length of train = 400 - 200 = 200 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train 120 meters long crosses a platform 280 meters long in 20 seconds. Find the speed of the train in km/h.
Correct Answer: Option D
Explanation:
Total distance = 120 + 280 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
Total distance = 120 + 280 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.
This question belongs to:
Maths
Time Speed and Distance
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