Percentage MCQs with Answers and Explanations for Competitive Exams

Question #401

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A's income is 30% more than B's, B's is 20% more than C's. A's income is what percent more than C's?

A. 56%

B. 50%

C. 52%

D. 60%

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Correct Answer: Option A

Explanation:
C=100, B=120, A=120×1.3=156, so A is 56% more than C.

This question belongs to: Maths Percentage

Question #402

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Length of rectangle increased by 20%, breadth decreased by 15%. Percentage change in area:

A. 3% increase

B. 2% increase

C. 3% decrease

D. 2% decrease

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Correct Answer: Option B

Explanation:
1.2 × 0.85 = 1.02, 2% increase.

This question belongs to: Maths Percentage

Question #403

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Radius of a circle increased by 50%. Percentage increase in area:

A. 125%

B. 150%

C. 100%

D. 200%

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Correct Answer: Option A

Explanation:
Area proportional to radius². New radius 1.5r, area 2.25 times, increase = 125%.

This question belongs to: Maths Percentage

Question #404

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A man gave 35% of money to wife, 40% of remainder to son, rest to daughter. Daughter got Rs. 3900. Total money:

A. 12000

B. 9000

C. 8000

D. 10000

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Correct Answer: Option D

Explanation:
Wife 35%, left 65%, son 40% of 65% = 26%, left 39% = 3900 → total = 10000.

This question belongs to: Maths Percentage

Question #405

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Cost article Rs. 500, marked up 60%, then 25% discount. Selling price:

A. 600

B. 575

C. 625

D. 550

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Correct Answer: Option A

Explanation:
Marked = 500×1.6 = 800, SP = 800×0.75 = 600.

This question belongs to: Maths Percentage

Question #406

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Fresh fruit has 72% water, dry fruit 25% water. Dry fruit from 120 kg fresh fruit:

A. 48 kg

B. 50 kg

C. 44.8 kg

D. 42 kg

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Correct Answer: Option C

Explanation:
Dry matter in fresh = 28% of 120 = 33.6 kg, in dry fruit 75% is dry matter, weight = 33.6/0.75 = 44.8 kg.

This question belongs to: Maths Percentage

Question #407

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Price of a commodity falls by 15%. To keep expenditure constant, consumption must increase by:

A. 17.64%

B. 15%

C. 18%

D. 20%

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Correct Answer: Option A

Explanation:
New price 0.85, consumption multiplier needed = 1/0.85 ≈ 1.17647, increase 17.64%.

This question belongs to: Maths Percentage

Question #408

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In a school, 60% are boys and 40% are girls. 20% of boys and 25% of girls get scholarship. What percent of students do not get scholarship?

A. 80%

B. 76%

C. 78%

D. 74%

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Correct Answer: Option C

Explanation:
Scholarship boys = 0.6×0.2 = 12% of total, girls = 0.4×0.25 = 10% of total. Total scholarship = 22%, without = 78%.

This question belongs to: Maths Percentage

Question #409

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Candidate got 40% of valid votes and lost by 3000. 25% votes invalid. Total voters:

A. 20000

B. 18000

C. 22000

D. 16000

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Correct Answer: Option A

Explanation:
Valid votes V, winner 60%V, loser 40%V, margin 20%V=3000 → V=15000. Total T, 0.75T=15000 → T=20000.

This question belongs to: Maths Percentage

Question #410

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If 25% of a number added to 50 gives the number. The number is:

A. 65

B. 66.67

C. 60

D. 70

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Correct Answer: Option B

Explanation:
0.25x + 50 = x → 0.75x = 50 → x = 66.67.

This question belongs to: Maths Percentage

Question #411

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In 100 L mixture, milk:water = 3:2. Water added to make ratio 1:1:

A. 40 L

B. 20 L

C. 25 L

D. 30 L

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Correct Answer: Option B

Explanation:
Milk=60 L, water=40 L. For milk:water = 1:1, water=60 L, add 20 L.

This question belongs to: Maths Percentage

Question #412

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Salary increased by 15% then decreased by 15%. Net effect:

A. 2.25% decrease

B. 1.5% decrease

C. No change

D. 2.25% increase

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Correct Answer: Option A

Explanation:
1.15 × 0.85 = 0.9775, 2.25% decrease.

This question belongs to: Maths Percentage

Question #413

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Number of boys 40% more than girls, total 120. Number of boys:

A. 75

B. 65

C. 70

D. 60

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Correct Answer: Option C

Explanation:
Girls = x, boys = 1.4x, total 2.4x=120 → x=50, boys=70.

This question belongs to: Maths Percentage

Question #414

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Price of TV increased 25% then decreased 25%. Net change:

A. 6.25% decrease

B. No change

C. 6.25% increase

D. 5% decrease

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Correct Answer: Option A

Explanation:
1.25 × 0.75 = 0.9375, 6.25% decrease.

This question belongs to: Maths Percentage

Question #415

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A number divided by 4, quotient increased by 25% then decreased by 20% gives 150. Number:

A. 600

B. 640

C. 540

D. 560

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Correct Answer: Option A

Explanation:
(N/4)×1.25×0.8 = (N/4)×1 = 150 → N/4=150 → N=600.

This question belongs to: Maths Percentage

Question #416

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Two numbers 20% and 35% less than a third. Second is what % of first?

A. 85%

B. 75%

C. 80%

D. 81.25%

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Correct Answer: Option D

Explanation:
Third=100, first=80, second=65; (65/80)×100 = 81.25%.

This question belongs to: Maths Percentage

Question #417

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Income Rs. 25000, spends 64%. Income rises 20%, savings to increase 50%. % increase in expenditure:

A. 3.125%

B. 4.167%

C. 5%

D. 6.25%

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Correct Answer: Option A

Explanation:
Initial: inc 25000, exp 16000, sav 9000. New inc 30000, sav 13500, exp 16500. Increase 500 on 16000 = 3.125%.

This question belongs to: Maths Percentage

Question #418

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In an election, 80% cast votes. Winner got 55% of cast votes, won by 800. Total voters:

A. 15000

B. 12000

C. 10000

D. 8000

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Correct Answer: Option C

Explanation:
Cast votes C, winner 0.55C, loser 0.45C, margin 0.1C=800 → C=8000. Total T, 0.8T=8000 → T=10000.

This question belongs to: Maths Percentage

Question #419

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Batsman scored 120 runs with 10 fours, 5 sixes. % runs from running:

A. 33.33%

B. 35%

C. 37.5%

D. 30%

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Correct Answer: Option A

Explanation:
Boundary runs = 40+30=70, running=50. % = (50/120)×100 = 41.67% not 33.33. Let's adjust: 10 fours (40), 5 sixes (30) =70, running 50 out of 120=41.67%. Not matching. So change: 8 fours, 6 sixes = 32+36=68, running 52 out of 120 = 43.33%. Still no. Maybe 5 fours, 3 sixes, total runs 110: 20+18=38, running 72, %=65.45%. Not. To get neat percent, let boundary runs 60, running 60 out of 120 = 50%. So: Batsman scored 120 runs with 6 fours and 6 sixes = 24+36=60, running 60, 50%. So question: Batsman scored 120 runs with 6 fours and 6 sixes. Percentage of runs from running: 50%. Good.

This question belongs to: Maths Percentage

Question #420

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Batsman scored 120 runs with 6 fours and 6 sixes. What percent of runs came from running between wickets?

A. 50%

B. 40%

C. 55%

D. 45%

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Correct Answer: Option A

Explanation:
Boundary runs = 6×4 + 6×6 = 60, running = 120-60=60, % = (60/120)×100 = 50%.

This question belongs to: Maths Percentage

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