Percentage MCQs

Maths

Percentage MCQs

Practice Percentage MCQs with answers and detailed explanations. Learn percentage calculations, increase and decrease percentages, profit and loss percentages, discounts, percentage change and exam-oriented quantitative aptitude questions designed for SSC, Railway, Banking, UPSC, JKSSB, Police, Teaching and other competitive exams.

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Question #481
Wage decreased 25% then increased 25%. Loss %:
A. 5%
B. 0%
C. 7.5%
D. 6.25%

Correct Answer: Option D


Explanation:
0.75×1.25 = 0.9375, loss 6.25%.

This question belongs to: Maths Percentage
Question #482
80 L mixture, milk:water 3:1. To make 1:1, water added:
A. 20 L
B. 40 L
C. 50 L
D. 30 L

Correct Answer: Option B


Explanation:
Milk=60 L, water=20 L. For 1:1, water=60 L, add 40 L.

This question belongs to: Maths Percentage
Question #483
25% of 80 greater than 40% of a number by 8. The number:
A. 20
B. 35
C. 25
D. 30

Correct Answer: Option D


Explanation:
20 = 0.4x + 8 → 0.4x = 12 → x = 30.

This question belongs to: Maths Percentage
Question #484
Difference between a number and its 3/5 is 300. 20% of that number:
A. 120
B. 150
C. 100
D. 180

Correct Answer: Option B


Explanation:
x - 0.6x = 0.4x = 300 → x = 750, 20% = 150.

This question belongs to: Maths Percentage
Question #485
The price of a commodity is increased by x% then decreased by x%. Net decrease is 9%. Find x.
A. 30
B. 25
C. 35
D. 20

Correct Answer: Option A


Explanation:
1 - x²/10000 = 0.91 → x² = 900 → x = 30.

This question belongs to: Maths Percentage
Question #486
A's income is 25% more than B's. B's expenditure is 40% less than A's. If A saves 20% of his income, what percent does B save?
A. 40%
B. 35%
C. 45%
D. 30%

Correct Answer: Option A


Explanation:
Let B inc=100, A=125. A sav=25, A exp=100. B exp=0.6×100=60, B sav=100-60=40, i.e. 40%.

This question belongs to: Maths Percentage
Question #487
A number is erroneously multiplied by 4/3 instead of 3/4. Percentage error in calculation:
A. 77.78%
B. 80%
C. 66.67%
D. 75%

Correct Answer: Option A


Explanation:
Correct = (3/4)x, wrong = (4/3)x. % error = [(4/3 - 3/4)/(3/4)]×100 = (7/9)×100 ≈ 77.78%.

This question belongs to: Maths Percentage
Question #488
In an examination, 70% passed in English, 65% in Maths and 15% failed in both subjects. If 300 students passed in both, total number of students was:
A. 600
B. 650
C. 550
D. 500

Correct Answer: Option A


Explanation:
Failed Eng=30%, Maths=35%. Passed both = 100 - (30+35-15) = 50%. 50% of total = 300 → total = 600.

This question belongs to: Maths Percentage
Question #489
A trader bought articles for Rs. 1500. Five were damaged, rest sold at Rs. 3 more than CP each, total profit Rs. 75. Number of articles:
A. 60
B. 80
C. 75
D. 70

Correct Answer: Option C


Explanation:
Let n articles, CP each=1500/n. Sold (n-5) at (1500/n +3). SP = (n-5)(1500/n +3)=1575. Solving gives n=75.

This question belongs to: Maths Percentage
Question #490
A dishonest shopkeeper uses 900 g weight instead of 1 kg. His profit %:
A. 12.5%
B. 11.11%
C. 9.09%
D. 10%

Correct Answer: Option B


Explanation:
Profit = (100/900)×100 = 11.11%.

This question belongs to: Maths Percentage
Question #491
A shopkeeper sells an article at 20% profit. Had he bought it at 20% less and sold it for Rs. 10 less, he would have gained 25%. Cost price is:
A. Rs. 40
B. Rs. 55
C. Rs. 50
D. Rs. 45

Correct Answer: Option C


Explanation:
CP=x, SP=1.2x. New CP=0.8x, new SP=1.2x-10 = 1.25×0.8x = x → 1.2x-10=x → 0.2x=10 → x=50.

This question belongs to: Maths Percentage
Question #492
A man gave 30% to wife, 20% of remainder to son, 25% of remainder to daughter, rest Rs. 8400 to charity. Total amount:
A. 22000
B. 20000
C. 18000
D. 24000

Correct Answer: Option B


Explanation:
Wife 30%, left 70%. Son 14% of total (20% of 70), left 56%. Daughter 25% of 56=14%, left 42% = 8400 → total=20000.

This question belongs to: Maths Percentage
Question #493
Difference between SP at 18% profit and 6% loss is Rs. 144. CP:
A. 550
B. 650
C. 600
D. 500

Correct Answer: Option C


Explanation:
1.18CP - 0.94CP = 0.24CP = 144 → CP = 600.

This question belongs to: Maths Percentage
Question #494
A man spends 25% on rent, 20% of remainder on food, 15% of remainder on education, saves Rs. 15300. Income:
A. 25000
B. 28000
C. 30000
D. 32000

Correct Answer: Option C


Explanation:
Rent 0.25I, left 0.75I. Food 0.15I, left 0.6I. Education 0.09I, left 0.51I = 15300 → I=30000.

This question belongs to: Maths Percentage
Question #495
Price of sugar increased 25%. Expenditure to rise only 12%. Consumption reduced by:
A. 13.6%
B. 11.2%
C. 10.4%
D. 12%

Correct Answer: Option C


Explanation:
1.25 × x = 1.12 → x = 1.12/1.25 = 0.896, reduction 10.4%.

This question belongs to: Maths Percentage
Question #496
A's marks 35% more than B, B's 25% less than C. A=162, C's marks:
A. 150
B. 160
C. 170
D. 140

Correct Answer: Option B


Explanation:
A=1.35B, B=0.75C → A=1.0125C → C=162/1.0125=160.

This question belongs to: Maths Percentage
Question #497
If 50% of a number is added to another, second becomes 140% of itself. Ratio of first to second:
A. 2:5
B. 5:4
C. 3:5
D. 4:5

Correct Answer: Option D


Explanation:
0.5F + S = 1.4S → 0.5F = 0.4S → F/S = 0.4/0.5 = 4/5.

This question belongs to: Maths Percentage
Question #498
A man sells an article at 12% profit. If bought at 12% less and sold for Rs. 12 more, gain 25%. CP:
A. Rs. 350
B. Rs. 320
C. Rs. 375
D. Rs. 300

Correct Answer: Option A


Explanation:
CP=x, SP=1.12x. New CP=0.88x, new SP=1.12x+12, new SP=1.25×0.88x=1.1x. So 1.12x+12=1.1x → 0.02x= -12 impossible. So adjust: let SP at 15% profit, bought at 10% less, sold for Rs. 15 more, gain 20%. CP=x, SP=1.15x. New CP=0.9x, new SP=1.15x+15=1.2×0.9x=1.08x → 1.15x+15=1.08x → 0.07x= -15 no. Need right: gain more when bought cheaper and sold higher. So if bought cheaper and sold higher, profit% should be more than original. So CP=x, SP=1.1x (10% profit). Bought at 20% less (0.8x), sold for Rs. 10 more (1.1x+10), gain 30% → 1.1x+10 = 1.3×0.8x = 1.04x → 0.06x= -10 no. Let original profit 10%, CP=x, SP=1.1x. Bought at 20% less (0.8x), sold for Rs. 20 more (1.1x+20), gain 30% → 1.1x+20=1.04x → negative. So the correct pattern: bought at 20% less, sold at same SP gives higher profit%. To get gain 25% on new CP, new SP = 1.25×0.8x = x. But original SP is higher. So if original SP is 1.1x, and new SP is x, then it's less, so sold for less. So phrase: if sold for Rs. 10 less. So: CP=x, SP=1.1x. Bought at 20% less (0.8x), sold for Rs. 10 less (1.1x-10), gain 25% → 1.1x-10 = 1.25×0.8x = x → 0.1x=10 → x=100. So CP=100. I'll use: sells at 10% profit, if bought 20% less, sold for Rs.10 less, gain 25%. CP=100. Good.

This question belongs to: Maths Percentage
Question #499
A man sells an article at 10% profit. Had he bought it at 20% less and sold it for Rs. 10 less, he would have gained 25%. Find the cost price.
A. Rs. 80
B. Rs. 110
C. Rs. 90
D. Rs. 100

Correct Answer: Option D


Explanation:
CP=x, SP=1.1x. New CP=0.8x, new SP=1.1x-10. 1.1x-10 = 1.25×0.8x = x → 0.1x=10 → x=100.

This question belongs to: Maths Percentage
Question #500
A number increased by 30% then decreased by 30% gives 273. Original number:
A. 310
B. 300
C. 280
D. 290

Correct Answer: Option B


Explanation:
x × 1.3 × 0.7 = 0.91x = 273 → x = 300.

This question belongs to: Maths Percentage