Ratio of present ages of A and B is 4:7. After 11 years, the ratio becomes 5:8. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 4:7. After 11 years, the ratio becomes 5:8. Present age of A is?
A. 40 years
B. 45 years
C. 36 years
D. 80 years
Answer: Option A
Solution (By JKExamLibrary)
Let ages 4k and 7k. Then (4k + 11)/(7k + 11) = 5/8. Solving gives k ≈ 10, age of A = 4*10 = 40.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
Two numbers are in the ratio 5:3 and their sum is 449. Find the numbers.
A. 296 and 147
B. 274 and 173
C. 280 and 168
D. 560 and 336

Correct Answer: Option C


Explanation:
Numbers = 5k and 3k. 5k + 3k = 449 ⇒ k = 56. Thus, numbers are 280 and 168.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
If a:b = 5:6 and b:c = 6:11, then a:b:c = ?
A. 4:6:12
B. 5:6:11
C. 5:7:11
D. 10:12:22

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 5:6, b:c = 6:11 ⇒ a:b:c = 5:6:11.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
If a:b = 8:3 and b:c = 3:4, then a:b:c = ?
A. 7:3:5
B. 8:3:4
C. 8:4:4
D. 16:6:8

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 8:3, b:c = 3:4 ⇒ a:b:c = 8:3:4.

This question belongs to: Maths Ratio and Proportion